Respuesta :
Answer:
0.3 N
Explanation:
mass of cork = 0.01 kg, density of cork = 250 kg/m^3
density of water = 1000 kg/m^3, g = 10 m/s^2
Tension in the rope = Buoyant force acting on the cork - Weight of the cork
Buoyant force = volume of cork x density of water x g
= mass x density of water x g / density of cork
= 0.01 x 1000 x 10 / 250 = 0.4 N
Weight of cork = mass of cork x g = 0.01 x 10 = 0.1 N
Thus, the tension in the rope = 0.4 - 0.1 = 0.3 N
Answer:
Tension = 0.3 N
Explanation:
As we know that the cork is inside water
so the buoyancy force on the cork is counter balanced by tension force in string and weight of the block
So the force equation is given as
[tex]F_b = T + mg[/tex]
now we will have
[tex]Volume = \frac{mass}{density}[/tex]
[tex]V = \frac{0.01}{250} = 4 \times 10^{-5} m^3[/tex]
now buoyancy force on the block is given by
[tex]F_b = \rho V g[/tex]
[tex]F_b = 1000(4 \times 10^{-5})(10)[/tex]
[tex]F_b = 0.4 N[/tex]
now by force balance equation
[tex]0.4 = T + 0.01(10)[/tex]
[tex]T = 0.4 - 0.1 = 0.3 N[/tex]
