Respuesta :

hdawg7797

Answer:

[tex]\frac{1}{36}[/tex]

Step-by-step explanation:

All die rolls have a 1 in 6 chance of landing on any specific number (because they have 6 equal sides). In probability, two independent events with probabilities a and b will occur concurrently [tex]a*b[/tex] of the time. In this case, [tex]a=b=\frac{1}{6} \to p=a*b=\frac{1}{6}*\frac{1}{6}=\frac{1}{36}[/tex]

imlittlestar

Answer:

Required probability = 1/36

Step-by-step explanation:

It is given that,single die is rolled twice

The outcomes of rolling a die are

1, 2, 3, 4, 5, and 6

Total = 6

To find the probability

Probability of getting 2 = 1/6

Probability of getting 5 = 1/6

Therefore probability of rolling a 2 the first time and a 5 the second time. = 1/6 * 1/6 = 1/36

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