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Identify an equation in point-slope form for the line parallel to y=-2/3x+8 that
passes through (4,-5).
O A. y+5 = (x-4)
O B. y 4= {(x+5)
O C. y-5--}(x+4)
O D. 4+5--xx-4)

Respuesta :

gmany

Answer:

[tex]\large\boxed{y+5=\dfrac{2}{3}(x-4)}[/tex]

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

Parallel lines have the same slope.

We have the equation in the slope-intercept form (y = mx + b)

[tex]y=-\dfrac{2}{3}x+8\to m=\dfrac{2}{3}[/tex]

Put to the point-slope equation value of the slope and the coordinates of the point (4, -5):

[tex]y-(-5)=\dfrac{2}{3}(x-4)\\\\y+5=\dfrac{2}{3}(x-4)[/tex]

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