Answer:
4 + [tex]\frac{1x}{3}[/tex] ≤ 2x + 12.
Step-by-step explanation:
Given : The sum of one third a number and 4 is at the most the sum of twice that number and 12.
To find : Write expression .
Solution : We have given statement
According to question :
Let the number = x
One third of a number = [tex]\frac{1x}{3}[/tex].
Sum of one third of number and 4 = 4 + [tex]\frac{1x}{3}[/tex].
Twice a number = 2x
Sum of twice that number and 12 = 2x + 12
So, sum of one third a number and 4 is at the most the sum of twice that number and 12.
4 + [tex]\frac{1x}{3}[/tex] ≤ 2x + 12.
greater than equal to sign for at most.
Therefore, 4 + [tex]\frac{1x}{3}[/tex] ≤ 2x + 12.
