Answer:
0.08
Step-by-step explanation:
A standard deck of 52 cards has four aces.
The sample space is:
n(S) = 52
Let A be the event that an ace is drawn from the deck.
Then,
n(A) = 4
So,
[tex]P(A) = \frac{n(A)}{n(S)}\\ =\frac{4}{52} \\=0.0769[/tex]
Rounding off to the nearest hundredth will give us:
0.08 ..