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Suppose two parents, a father with the genotype AaBbCcDdee and a mother with the genotype aabbCcDDEe, wanted to have children. Assume each locus follows Mendelian inheritance patterns for dominance. What proportion of the off spring will have each of the following characteristics? Round your answers to two decimal places.

Respuesta :

vicobusso

Answer:

Half of them

Explanation:

Each letter represent a character.

Capital letter represent dominance.

When you complete punnet's charters (one of each character) you will know the appearence percentage.

Letter A

Twice capital A appears = 50%

Letter B

Twice capital B appears = 50%

Letter C

Three times capital C appears = 75%

Letter D

Four times capital D appears = 100%

Ver imagen vicobusso
marianaegarciaperedo

The fork line method is used to get genotypic and phenotypic proportions. In this case, 0.03 of the progeny have the father's genotype, 0.03 have the mother's genotype, 0.09 looks like the father, 0.09 looks like the mother, and 0.81 are different from both parents.

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Available data:

  • Five diallelic genes
  • Mendelian inheritance patterns for dominance
  • father ⇒  AaBbCcDdee
  • mother ⇒  aabbCcDDEe

Cross: Mother x Father

Parentals) aabbCcDDEe x AaBbCcDdee

To avoid making a Punnett square -which whould be very complex-, we will perform crosses separately for each gene, and then multiply their proportions. This is the fork line method, and is useful to get the proportions of the desired genotypes and phenotypes among the progeny.

Gene A:

Parentals) aa   x    Aa

Gametes) a  a     A   a

F1) 1/2 = 50% Aa  

    1/2 = 50% aa

Gene B:

Parentals) bb   x    Bb

Gametes) b  b       B   b

F1) 1/2 = 50% Bb  

    1/2 = 50% bb

Gene C:

Parentals) Cc   x    Cc

Gametes) C   c      C    c

F1) 1/4 = 25% CC  

    1/2 = 50% Cc

    1/4 = 25% cc

Gene D:

Parentals) DD   x    Dd

Gametes) D   D      D    d

F1) 1/2 = 50% DD

    1/2 = 50% Dd

Gene E:

Parentals) Ee   x    ee

Gametes) E   e     e   e

F1) 1/2 = 50% Ee

    1/2 = 50% ee

F1) Genotypes

a. Same genotype as the father ⇒ AaBbCcDdee

1/2 Aa x 1/2 Bb x 1/2 Cc x 1/2 Dd x 1/2 ee = 1/32 = 0.03 AaBbCcDdee

[tex]1/2 Aa x 1/2 Bb x 1/2 Cc x 1/2 Dd x 1/2 ee = 1/32 = 0.03 AaBbCcDdee[/tex]

b. same genotype as the mother ⇒ aabbCcDDEe

1/2 aa x 1/2 bb x 1/2 Cc x 1/2 DD x 1/2 Ee = 1/32 = 0.03 aabbCcDDEe

[tex]1/2 aa x 1/2 bb x 1/2 Cc x 1/2 DD x 1/2 Ee = 1/32 = 0.03 aabbCcDDEe[/tex]

     Phenotypes

c. phenotypically resemble the father  ⇒ A-B-C-D-ee

1/2 A-x 1/2 B- x 3/4 C- x 1 D- x 1/2 ee = 3/32 = 0.09 A-B-C-D-ee

[tex]1/2 A-x 1/2 B- x 3/4 C- x 1 D- x 1/2 ee = 3/32 = 0.09 A-B-C-D-ee[/tex]

d. phenotypically resemble the mother ⇒ aabbC-D-E-

1/2 aa x 1/2 bb x 3/4 C- x 1 D- x 1/2 D- = 3/32 = 0.09 aabbC-D-E-

[tex]1/2 aa x 1/2 bb x 3/4 C- x 1 D- x 1/2 D- = 3/32 = 0.09 aabbC-D-E-[/tex]

e. phenotypically resemble neither parent 26/32 = 0.81

  • 1/2 A- x 1/2 B- x 3/4 C- x 1 D- x 1/2 E- = 3/32 A-B-C-D-E-

[tex]1/2 A- x 1/2 B- x 3/4 C- x 1 D- x 1/2 E- = 3/32 A-B-C-D-E-[/tex]

  • 1/2 A- x 1/2 B- x 1/4 cc x 1 D- x 1/2 E- = 1/32 A-B-ccD-E-

[tex]1/2 A- x 1/2 B- x 1/4 cc x 1 D- x 1/2 E- = 1/32 A-B-ccD-E-[/tex]

  • 1/2 A- x 1/2 B- x 1/4 cc x 1 D- x 1/2 ee = 1/32 A-B-ccD-ee

[tex]1/2 A- x 1/2 B- x 1/4 cc x 1 D- x 1/2 ee = 1/32 A-B-ccD-ee[/tex]

  • 1/2 A- x 1/2 bb x 3/4 C- x 1 D- x 1/2 E- = 3/32 A-bbC-D-E-

[tex]1/2 A- x 1/2 bb x 3/4 C- x 1 D- x 1/2 E- = 3/32 A-bbC-D-E-[/tex]

  • 1/2 A- x 1/2 bb x 1/4 cc x 1 D- x 1/2 E- = 1/32 A-bbccD-E-

[tex]1/2 A- x 1/2 bb x 1/4 cc x 1 D- x 1/2 E- = 1/32 A-bbccD-E-[/tex]

  • 1/2 A- x 1/2 bb x 3/4 C- x 1 D- x 1/2 ee = 3/32 A-bbC-D-ee

[tex]1/2 A- x 1/2 bb x 3/4 C- x 1 D- x 1/2 ee = 3/32 A-bbC-D-ee[/tex]

  • 1/2 A- x 1/2 bb x 1/4 cc x 1 D- x 1/2 ee = 1/32 A-bbccD-ee

[tex]1/2 A- x 1/2 bb x 1/4 cc x 1 D- x 1/2 ee = 1/32 A-bbccD-ee[/tex]

  • 1/2 aa x 1/2 B- x 3/4 C- x 1 D- x 1/2 E- = 3/32 aaB-C-D-E-

[tex]1/2 aa x 1/2 B- x 3/4 C- x 1 D- x 1/2 E- = 3/32 aaB-C-D-E-[/tex]

  • 1/2 aa x 1/2 B- x 3/4 C- x 1 D- x 1/2 ee = 3/32 aaB-C-D-ee

[tex]1/2 aa x 1/2 B- x 3/4 C- x 1 D- x 1/2 ee = 3/32 aaB-C-D-ee[/tex]

  • 1/2 aa x 1/2 B- x 1/4 cc x 1 D- x 1/2 E- = 1/32 aaB-ccD-E-

[tex]1/2 aa x 1/2 B- x 1/4 cc x 1 D- x 1/2 E- = 1/32 aaB-ccD-E-[/tex]

  • 1/2 aa x 1/2 B- x 1/4 cc x 1 D- x 1/2 ee = 1/32 aaB-ccD-ee

[tex]1/2 aa x 1/2 B- x 1/4 cc x 1 D- x 1/2 ee = 1/32 aaB-ccD-ee[/tex]

  • 1/2 aa x 1/2 bb x 1/4 cc x 1 D- x 1/2 E- =1/32 aabbccD-E-

[tex]1/2 aa x 1/2 bb x 1/4 cc x 1 D- x 1/2 E- =1/32 aabbccD-E-[/tex]

  • 1/2 aa x 1/2 bb x 3/4 C- x 1 D- x 1/2 ee = 3/32 aabbC-D-ee

[tex]1/2 aa x 1/2 bb x 3/4 C- x 1 D- x 1/2 ee = 3/32 aabbC-D-ee[/tex]

  • 1/2 aa x 1/2 bb x 1/4 cc x 1 D- x 1/2 ee = 1/32 aabbccD-ee

[tex]1/2 aa x 1/2 bb x 1/4 cc x 1 D- x 1/2 ee = 1/32 aabbccD-ee[/tex]

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