Answer:
[tex]\sqrt{28} \approx 5.3[/tex]
Step-by-step explanation:
The Pythagorean Theorem says if you have a right triangle, then relationship between the three sides is the sum of the square of each leg is the hypotenuse squared.
So [tex]a^2+b^2=c^2[/tex]
where a and b are legs and c is the hypotenuse.
Plug in your a,b, and c. In this case it is a,6, and 8.
This means we have
[tex]a^2+6^2=8^2[/tex]
Simplify where you can before we begin the solving (the moving around of things to other sides).
[tex]a^2+36=64[/tex]
Now time for the solving. We are first going to get [tex]a^2[/tex] by itself.
To do this, we just need to subtract 36 on both sides giving us:
[tex]a^2=64-36[/tex]
[tex]a^2=28[/tex]
Now to get rid of the square on a, just square root both sides:
[tex]a=\sqrt{28}[/tex].
