Answer:
[tex]4 \frac{5}{6}[/tex]
Step-by-step explanation:
We can write [tex]1 \frac{2}{6}[/tex] as [tex]\frac{8}{6}[/tex] and we can write [tex]3 \frac{4}{8}[/tex] as [tex]\frac{28}{8}[/tex]. So the question becomes [tex]\frac{8}{6} + \frac{28}{8}[/tex]. We can simplify both fractions so that the expression is [tex]\frac{4}{3} + \frac{7}{2}[/tex] and to add the two fractions we need to find a common denominator. The least common multiple of 2 and 3 is 6, so we want the denominator to be 6 in both fractions. To do this, we multiply [tex] \frac{4}{3} [/tex] by [tex] \frac{2}{2} [/tex] and we multiply [tex]\frac{7}{2}[/tex] by [tex]\frac{3}{3}[/tex].
So finally we get [tex]\frac{4}{3} \times \frac{2}{2} + \frac{7}{2} \times \frac{3}{3}[/tex], which is [tex]\frac{8}{6} + \frac{21}{6}[/tex], which is [tex]\frac{29}{6}[/tex].
And now all we have to do is rewrite the improper fraction [tex]\frac{29}{6}[/tex]. Notice 6 goes into 29 exactly 4 times, with a remainder of 5. So the expression simplifies to [tex]4 \frac{5}{6}[/tex]
