please help ASAP !


Consider the quadratic function f(x)=x^2−5x−6.



Determine the following: (enter all numerical answers as integers, fractions, or decimals):



The smallest x-intercept is x=____ .



The largest x-intercept is x=____ .



The y-intercept is y=_____ .



The vertex is ( ___ , ___ ).



The line of symmetry has the equation _____.

Respuesta :

Answer:

Part 1) The smallest x-intercept is x=-1

Part 2) The largest x-intercept is x=6

Part 3) The y-intercept is y=-6

Part 4) The vertex is the point (2.5,-12.25)

Part 5) The equation of the line of symmetry is x=2.5

Step-by-step explanation:

we have

[tex]f(x)=x^{2}-5x-6[/tex]

step 1

Find the x-intercepts

we know that

The x-intercept is the value of x when the value of the function is equal to zero

so

equate the function to zero

[tex]x^{2}-5x-6=0[/tex]

The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to

[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]

in this problem we have

[tex]x^{2}-5x-6=0[/tex]

so

[tex]a=1\\b=-5\\c=-6[/tex]

substitute in the formula

[tex]x=\frac{-(-5)(+/-)\sqrt{-5^{2}-4(1)(-6)}} {2(1)}[/tex]

[tex]x=\frac{5(+/-)\sqrt{49}} {2}[/tex]

[tex]x=\frac{5(+/-)7} {2}[/tex]

[tex]x=\frac{5(+)7} {2}=6[/tex]

[tex]x=\frac{5(-)7} {2}=-1[/tex]

therefore

The x-intercepts are

x=-1 and x=6

The smallest x-intercept is x=-1

The largest x-intercept is x=6

step 2

Find the y-intercept

we know that

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

[tex]f(0)=(0)^{2}-5(0)-6[/tex]

[tex]f(0)=-6[/tex]

therefore

The y-intercept is y=-6

step 3

Find the vertex

we know that

The equation of a vertical parabola into vertex form is equal to

[tex]f(x)=a(x-h)^{2}+k[/tex]

where

(h,k) is the vertex

Convert the function into vertex form

[tex]f(x)=x^{2}-5x-6[/tex]

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex]f(x)+6=(x^{2}-5x)[/tex]

Complete the square, Remember to balance the equation by adding the same constants to each side

[tex]f(x)+6+2.5^{2}=(x^{2}-5x+2.5^{2})[/tex]

[tex]f(x)+12.25=(x^{2}-5x+6.25)[/tex]

Rewrite as perfect squares

[tex]f(x)+12.25=(x-2.5)^{2}[/tex]

[tex]f(x)=(x-2.5)^{2}-12.25[/tex]

The vertex is the point (2.5,-12.25)

step 4

Find the equation of the line of symmetry

we know that

In a vertical parabola the equation of the line of symmetry is equal to the x-coordinate of the vertex

we have

vertex (2.5,-12.25)

The x-coordinate of the vertex is 2.5

therefore

The equation of the line of symmetry is x=2.5