Answer:
- line segment of length 8 between the vertices at (-1, -2) and (-1, 6)
Explanation:
The equation can be rearranged to standard form.
(y^2 -4y) -4(x^2 +2x) = 16
(y^2 -4y +4) -4(x^2 +2x +1) = 16 +4 -4
(y -2)^2 -4(x +1)^2 = 16
(y -2)^2 /16 -(x +1)^2/4 = 1
This is of the form ...
(y -k)^2/a^2 -(x -h)^2/b^2 = 1
where the transverse axis is 2a and the center is (h, k). Here, a=4, so 2a = 8.
The transverse axis is a vertical line segment of length 8, centered on (-1, 2).
