The pH of the buffer solution prepared from acetic acid and calcium acetate in sufficient water is 4.84.
Molarity of the acid and base
H(Ac) = 0.4/1.4L = 0.2857 M
Ca(OH)₂ = 0.25/1.4L = 0.17857 M
Total molarity
= 0.2857 M H(Ac) + 0.17857 M Ca(OH)₂
= 0.2857 M H(Ac) + 2(0.17857) OH⁻
= 0.2857 M H(Ac) + 0.3571 M OH⁻
H(Ac) ⇄ H⁺ OH⁻
0.2857 M ⇄ 0.3571 M
pH of the buffer solution
[tex]H^+ = \frac{[K_a][H(_{AC}]}{OH^-} \\\\H^+ = \frac{(1.8 \times 10^{-5}) (0.2857)}{(0.3571)} \\\\H^+ = 1.44\times 10^{-5}[/tex]
pH = -Log(H⁺)
pH = - Log(1.44 x 10⁻⁵)
pH = 4.84
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