Find the midpoint between (4,-1) and (3,2)

Midpoint has form of,
[tex]M(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})[/tex]
We can insert the data,
[tex]M(\dfrac{4+3}{2},\dfrac{-1+2}{2})[/tex]
Which simplifies to,
[tex]\boxed{M(3.5, 0.5)}[/tex]
Hope this helps.
r3t40