Respuesta :
Answer:
x = 3, x = - 3, x = - 1 with multiplicity 2
Step-by-step explanation:
Given that x = 3 and x = - 3 are zeros then
(x - 3) and (x + 3) are factors and
(x - 3)(x + 3) = x² - 9 ← is a factor
Using long division to divide the polynomial by x² - 9 gives
quotient = x² + 2x + 1 = (x + 1)² and equating to zero
(x + 1)² = 0 ⇒ x + 1 = 0 ⇒ x = - 1 with multiplicity 2
Hence the zeros of the polynomial are
x = 3, x = - 3, x = - 1 with multiplicity 2
