Answer:
B) 28.53 unit²
Step-by-step explanation:
The diagonal AD divides the quadrilateral in two triangles:
- Triangle ABD
- Triangle ACD
Area of Quadrilateral will be equal to the sum of Areas of both triangles.
i.e.
Area of ABCD = Area of ABD + Area of ACD
Area of Triangle ABD:
Area of a triangle is given as:
[tex]Area = \frac{1}{2} \times base \times height[/tex]
Base = AB = 2.89
Height = AD = 8.6
Using these values, we get:
[tex]Area = \frac{1}{2} \times 2.89 \times 8.6 = 12.43[/tex]
Thus, Area of Triangle ABD is 12.43 square units
Area of Triangle ACD:
Base = AC = 4.3
Height = CD = 7.58
Using the values in formula of area, we get:
[tex]Area = \frac{1}{2} \times 4.3 \times 7.58 = 16.30[/tex]
Thus, Area of Triangle ACD is 16.30 square units
Area of Quadrilateral ABCD:
The Area of the quadrilateral will be = 12.43 + 16.30 = 28.73 units²
None of the option gives the exact answer, however, option B gives the closest most answer. So I'll go with option B) 28.53 unit²
