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To titrate 15.00 milliliters of an unknown HCl sample, use 25.00 milliliters of a standard 0.2000 M NaOH titrant. What is the molarity of the HCl

Respuesta :

CaptainCaleb
Using Formula M1V1=M2V2

HCl+NaOH -> NaCl + H2O
1:1 ratio

M1=Molarity of HCl = X
V1 = Volume of HCl = 15mL = 0.015L

M2 = Molarity of NaOH = 0.2M
V2 = Volume of NaOh = 25mL = 0.025L

(XM)(0.015L)=(0.2M)(0.025L)
Isolate unknown:
(XM)=[(0.2M)(0.025L)/(0.015L)]
XM=0.33M

Hence, Molarity of HCl is = 0.33 Moles

Answer:

Molarity of HCl = 0.3333M

Explanation:

Given:

Volume of HCl = 15.00 ml

Volume of NaOH = 25.00 ml

Molarity of NaOH = 0.2000 M

To determine:

Molarity of HCl

Explanation:

The titration reaction is:

[tex]HCl + NaOH \rightarrow NaCl + H2O[/tex]

Based on the reaction stoichiometry:

1 mole of HCl reacts with 1 mole of NaOH to form 1 mole of NaCl and water.

Therefore the molar ratio of HCl:NaOH = 1:1

[tex]Molarity = \frac{Moles}{Volume(L)}[/tex]

[tex]Moles(NaOH)=0.2000moles/L*0.025 L = 0.005moles[/tex]

Moles of NaOH consumed = Moles of HCl present = 0.005 moles

[tex]Molarity(HCl)=\frac{Moles}{Volume}=\frac{0.005moles}{0.015L}=0.3333M[/tex]