rubendeanda02p1y63u rubendeanda02p1y63u

10-07-2019
Mathematics

contestada

Find all solutions to the equation sin(3x)cosx+sinx cos(3x)=0 on the interval [0,2pi]

a- x=0,pi/4,pi/2,3pi/4,pi,3pi/2,2pi
b- x=0,pi/2,pi,3pi/2,2pi
c- x=0,pi,2pi
d- x=0,pi/2,3pi/2

Respuesta :

mamatha8186 mamatha8186

10-07-2019

Answer:

Step-by-step explanation:

Please have in mind that sin(A - B) = sin(A)cos(B) - cos(A)sin(B)

So what we do is:

sin(3x)cos(x) - sin(x)cos(3x) = 0 => sin(3x - x) = 0

sin(2x) = 0

2x = 0, π, 2π, 3π, 4π

x = 0, π/2, π, 3π/2, 2π

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