Answer:
Option B, 58°
Step-by-step explanation:
In the given figure AB ║ CD and BC ║ DE ( given )
Since BC ║ DE and BC ⊥ AC
So DE will also be perpendicular to CE
m ∠ BAC = 32° [given]
Since AB ║ CD and line AE is transverse
Then ∠BAC ≅ ∠DCE ≅ 32°
Now in ΔDEC.
∠DCE + ∠CED + ∠EDC = 180°
32° + 90° + ∠EDC = 180°
122° + ∠EDC = 180°
∠EDC = 180 -122
= 58°
Option B, 58° is the answer.
