Respuesta :
Answer: Third option is correct.
Step-by-step explanation:
Since we have given that
Total number of students = 180
Number of students who signed for canoeing (C) = 72
Number of students who signed for trekking (T) = 23
Number of student who signed for trekking is also signed for canoeing = 13
Number of students who only signed for canoeing (C) = 72-13=59
Number of students who only signed for trekking (T) = 23-13=10
So, Number of students who signed up either for canoeing or trekking is given by
[tex]n(C\cup T)=n(C)+n(T)-n(C\cap T)\\\\n(C\cup T)=72+23-13\\\\n(C\cup T)=95-13\\\\n(C\cup T)=82[/tex]
So, Number of students who signed up neither for canoeing not trekking is given by
[tex]n(C\cup T)'=n(U)-n(C\cup T)\\\\n(C\cup T)'=180-82\\\\n(C\cup T)'=98[/tex]
So, Percentage of students signed up for neither canoeing nor trekking is given by
[tex]\dfrac{98}{180}\times 100\\\\=54.4\%\\\\\approx 54\%[/tex]
Hence, Third option is correct.
