Answer:
the concentration remains = 0.138 M
Explanation:
Let us calculate the charge passed:
The charge passed during the electrolysis = current X time(s)
charge passed = 2.40X30X60= 2160 C
we know that
96485 C = 1 F
Therefore 2160 C = 0.0224 F
according to Faraday's law of electrolysis if we pass one Faraday of charge through an electrolytic solution, 1 gram equivalent of metal will be deposited.
the gram equivalent of nickel deposited = 0.0224
The moles of Nickel deposited = 0.0224/2 = 0.0112 mol
the initial moles of Nickel ions present in solution is
[tex]moles=molarityXvolume(L)=0.250X0.1=0.0250mol[/tex]
The moles of nickel ion gets consumed = 0.0112
So moles of nickel ion left after electrolysis = 0.0138
[tex][Ni^{+2}]=\frac{moles}{volume(L)}\frac{0.0138}{0.1}=0.138M[/tex]
