Answer:
[tex]Q = 4.63 \times 10^6 J[/tex]
Explanation:
As we know that melting point of silver is
T = 961.8 degree C
Latent heat of fusion of silver is given as
L = 111 kJ/kg
specific heat capacity of silver is given as
[tex]s = 240 J/kg C[/tex]
now we will have
[tex]Q = ms\Delta T + mL[/tex]
[tex]\Delta T = 961.8 - 20 [/tex]
[tex]\Delta T = 941.8 degree C[/tex]
now from above equation
[tex]Q = (13.74)(240)(941.8) + (13.74)(111 \times 10^3)[/tex]
[tex]Q = 3.1 \times 10^6 + 1.53 \times 10^6[/tex]
[tex]Q = 4.63 \times 10^6 J[/tex]
