Explanation:
The electric field of an isolated charged parallel-plate capacitor is given by :
[tex]E=\dfrac{q}{A\epsilon_o}[/tex]........(1)
Where
q is the electric charge
A is the area of cross section of parallel plate
It is clear from equation (1) that the electric field of a parallel plate capacitor is directly proportional to the charge on the plate and inversely proportional to the area of cross section of a plate.
So, the correct option is (E) i.e. "none of the above".
