Answer:
6.93 volts
Explanation:
q = magnitude of charge on proton = 1.6 x 10⁻¹⁹ C
r = radius of the orbit = 2.08 x 10⁻¹⁰ m
V = Electric potential due to proton on electron
Electric potential due to proton on electron is given as
[tex]V = \frac{kq}{r}[/tex]
Inserting the values
[tex]V = \frac{(9\times 10^{9})(1.6\times 10^{-19})}{2.08\times 10^{-10}}[/tex]
V = 6.93 volts
