Answer:
The acceleration and time are 1.95 m/s and 12.5 s.
Explanation:
Given that,
Speed = 80 ft/s =24.384 m/s
Distance = 500 ft =152.4 m
We need to calculate the acceleration
Using third equation of motion
[tex]v^2-u^2= 2as[/tex]
[tex]a = \dfrac{v^2-u^2}{2s}[/tex]
Where, u = initial velocity
v = final velocity
a = acceleration
s = distance
Put the value in the equation
[tex]a=\dfrac{(24.384)^2-0}{2\times152.4}[/tex]
[tex]a=1.95\ m/s^2[/tex]
We need to calculate the time
Using first equation of motion
[tex]v=u+at[/tex]
[tex]t =\dfrac{v-u}{a}[/tex]
[tex]t=\dfrac{24.384-0}{1.95}[/tex]
[tex]t =12.5\ s[/tex]
Hence, The acceleration and time are 1.95 m/s and 12.5 s.
