Answer:
3.7 x 10⁷ m/s
Explanation:
ΔV = Potential difference through which the proton moves = 7.15 MV = 7.15 x 10⁶ Volts
q = magnitude of charge on the proton = 1.6 x 10⁻¹⁹ C
v = speed of the proton as it reach zero potential region
m = mass of the proton = 1.66 x 10⁻²⁷ kg
Using conservation of energy
Kinetic energy gained by proton = Electric potential energy lost
(0.5) m v² = q ΔV
(0.5) (1.66 x 10⁻²⁷) v² = (1.6 x 10⁻¹⁹) (7.15 x 10⁶)
v = 3.7 x 10⁷ m/s
