Answer:
[tex]s = 9.6\times 10^{-12}kg/s[/tex]
Explanation:
Given:
Solute Diffusion rate = 4.0 × 10⁻¹¹ kg/s
Area of cross-section = 0.50 cm²
Length of channel =0.25 cm
Now for the new channel
Area of cross-section = 0.30 cm²
Length of channel =0.10 cm
let the Solute Diffusion rate of new channel = s
now equating the diffusion rate per unit volume for both the channels
[tex]\frac{4\times 10^{-11}}{0.50\times 0.25}=\frac{s}{0.30\times 0.10}[/tex]
thus,
[tex]s = 9.6\times 10^{-12}kg/s[/tex]
