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Two cars approach an extremely icy four-way perpendicular intersection. Car A travels northward at 10 m/s and car B is traveling eastward. They collide and stick together, traveling at 41.5° north of east. What was the initial velocity of car B (in m/s)? (Enter the magnitude. Assume the masses of the cars are equal.)

Respuesta :

Answer:

v = 11.3 m/s

Explanation:

Since there is no external force on the system of two cars

so here momentum of the system of two cars will remain constant

it is given here that two cars combined and move together at 41.5 degree North of East after collision

so here direction of final momentum is given as

[tex]tan\theta = \frac{P_y}{P_x}[/tex]

now we have initial momentum in the same direction

[tex]P_1 = m(10 m/s)\hat j[/tex]

[tex]P_2 = mv\hat i[/tex]

now we have

[tex]\frac{P_1}{P_2} = tan\theta[/tex]

[tex]\frac{m(10 m/s)}{mv} = tan41.5[/tex]

[tex]\frac{10}{v} = 0.88[/tex]

[tex]v = 11.3 m/s[/tex]

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