Answer:
Temperature of neon gas = 875 K
Explanation:
Using Ideal gas equation as:
PV=nRT
Where,
P is the pressure of the gas
V is the volume of the gas
n is the number of moles
R is the gas constant
T is the temperature
Also,
[tex]moles=\frac{Mass(m)}{Molar\ mass (M)}[/tex]
[tex]Density (\rho)=\frac{Mass(m)}{Volume(V)}[/tex]
The ideal gas equation can be written as:
[tex]P=\frac{Mass(m)}{Molar\ mass (M)\times Volume(V)}\times RT[/tex]
Thus,
[tex]P=\frac{Density (\rho)}{Molar\ mass (M)}\times RT[/tex]
[tex]P\times M=Density (\rho)\times RT[/tex]
As Density and Pressure is constant , We only consider molar mass and Temperature which are directly proportional according to the equation above as:
[tex]\frac {M_1}{T_1}=\frac {M_2}{T_2}[/tex]
Data given for He:
Temperature (T₁) = 175 K
Molar mass of He (M₁)= 4 g/mol
For Ne:
Temperature (T₂)= ?
Molar mass of He (M₂)= 20 g/mol
Applying in the equation,
[tex]T_2=\frac {M_2}{T_1} \times {M_1}[/tex]
[tex]T_2=\frac {20 g{mol}^{-1}}{175 K} \times {4 g{mol}^{-1}}[/tex]
[tex]T_2=875 K atm[/tex]
Temperature of neon gas = 875 K
