Respuesta :
[tex]4x^2-12x+29=20 \\4x^2-12x+9=0\\(2x-3)^2=0\\2x-3=0\\2x=3\\x=\dfrac{3}{2}[/tex]
With these kind of equations you want to use the quadratic formula. These problems take time, so don't fret you'll get there! :)
Quadratic formula:
-b +- √b^2-4(a)(c)
--------------------------
2(a)
Next find your a, b, and c!
a= 4
b=12
c=29
Time to plug those answers in.
12 +- √(-12)^2-4(4)(9)
-------------------------------
2(4)
Next solve everything in the radical first! Then the bottom.
12 +- √144-144
----------------------- ~ x=12/8 ~ x=3/2
8
You get: x=3/2!