Respuesta :
Answer:
a)1.13×10³
b)1.6×10³
Explanation:
Given:
Boltzmann's constant (K)=1.38×10^-23 J/K
atmoic mass of helium = 4 AMU or 4×1.66×10^-27kg
a)The formula for RMS speed (Vrms) is given as
[tex]Vrms=\sqrt{\frac{3KT}{m} }[/tex]
where
K= Boltzmann's constant
T= temperature
m=mass of the gas
[tex]Vrms=\sqrt{\frac{3\times 1.38\times 10^{-23}\times 206}{6.64\times 10^{-27}}}[/tex]
[tex]Vrms=1.13\times 10^{3}m/s[/tex]
b) RMS speed of helium when the temperature is doubled
[tex]Vrms=\sqrt{\frac{3\times 1.38\times 10^{-23}\times 2\times 206}{6.64\times 10^{-27}}}[/tex]
[tex]Vrms=1.598\times 10^{3}m/s[/tex]
