Answer:[tex]V_{air}=0.259m/s[/tex]
[tex]V_{water}=0.01293m/s[/tex]
Explanation:
Given data
Length of pipe[tex]\left ( L\right )[/tex]=13cm=0.13m
From tables at [tex]T=30^{\circ}[/tex]
Kinematic viscosity of air[tex]\left ( \mu\right )=1.6036\times 10{-5} m^{2}/s[/tex]
and reynolds number is given by
Re=[tex]\frac{V\times \characteristic\ length}{Kinematic visocity}[/tex]
Flow is laminar up to Re.no. 2100
Re=[tex]\frac{V\times L}{1.6036\times 10{-5}}[/tex]
2100=[tex]\frac{V\times 0.13}{1.6036\times 10{-5}}[/tex]
V=0.259 m/s
For water
Kinematic viscosity of water[tex]\left ( \mu\right )=0.801\times 10{-6}m^{2}/s[/tex]
2100=[tex]\frac{V\times 0.13}{0.801\times 10{-6}}[/tex]
V=0.01293 m/s
