Respuesta :
Both 3 and x are common to all of the expressions so we can factor them out...
3x^3 - 3x^2 -18x
3x (x^2 -x -6)
Now factor inside the parentheses
3x(x - 3)(x + 2)
Done. Answer C (or the 3rd one down)
3x^3 - 3x^2 -18x
3x (x^2 -x -6)
Now factor inside the parentheses
3x(x - 3)(x + 2)
Done. Answer C (or the 3rd one down)
Answer:
(C)[tex]3x(x-3)(x+2)[/tex]
Step-by-step explanation:
The given equation is:
[tex]3x^3-3x^2-18x[/tex]
Upon solving this equation, we get
Taking 3x common from all the terms of the above equation,
[tex]3x(x^2-x-6)[/tex]
Now, factorizing the above equation, we have
[tex]3x(x^2-3x+2x-6)[/tex]
[tex]3x(x(x-3)+2(x-3))[/tex]
[tex]3x(x-3)(x+2)[/tex]
which is the required factorized form of the above equation.
Hence, option C is correct.