The correct answer is:
[tex]\text{D) If }EFG \cong HJK, \text{ then } HJK \cong EFG.[/tex]
Explanation:
The symmetric property states that if two quantities are equal (or congruent), you can "flip" them around the equals sign (or congruence sign).
This means since EFG is congruent to HJK, then HJK is congruent to EFG.