use distanc formula
distance betwen ponts (x1,y1) and (x2,y2) is
D=[tex] \sqrt{(x2-x1)^{2}+(y2-y1)^{2}} [/tex]
distance from art to gass is
from (6,1) to (4,4)
input to find
D=[tex] \sqrt{(4-6)^{2}+(4-1)^{2}} [/tex]=√13
distance from cemetary to animal is
from (3,-4) to (6,-2)
D=[tex] \sqrt{(6-3)^{2}+(-2-(-4))^{2}} [/tex]=√13
how does √13 compare with√13
they are equal
compare dissacne betwen police and stadium then police and art
police to stadium is
(0,-4) to (-2,3)
D=[tex] \sqrt{(-2-0)^{2}+(3-(-4))^{2}} [/tex]=√53= aprox 7.28011
police to art is
(0,-4) to (6,1)
D=[tex] \sqrt{(6-0)^{2}+(1-(-4))^{2}} [/tex]=√61= aprox 7.81025
from police to art is longer by (7.81025-7.28011=0.53015) 0.53015 units
