9)
Seventy-five times a negative integer minus 36 equals 21 times the square of the negative integer. Which equation could be used to solve for the unknown negative integer?

Respuesta :

lime52
-75x - 36 = -21x²

-75x   Seventy-five times a negative integer
-36   Minus 36
=   Equals
-21x²   The square of the negative integer

Hope this helps!

Answer:

[tex]21 x^2 +75 x+36 =0[/tex]

Step-by-step explanation:

Let us assume that the negative integer is  -x

Now we have

Seventy - five times a negative integer = [tex]75 (-x ) = -75 x[/tex]

Seventy - five times a negative integer minus 36 = [tex]-75x - 36[/tex]

Square of negative integer = [tex](-x)^2 = x^2[/tex]

21 times the square of negative integer = [tex]21 x^2[/tex]

Now it is given that

Seventy - five times a negative integer minus 36  is equal to 21 times the square of negative integer

So we have

[tex]-75x -36 = 21 x^2[/tex]

We can also try to write this in standard form by bring all the terms to one side

[tex]-75x = 21 x^2 +36[/tex]  ( adding 36 to both sides)

[tex]0 = 21 x^2 +75 x+ 36[/tex]  ( adding 75x to both sides )

[tex]21 x^2 +75 x+36 =0[/tex]  ( Answer )