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Figure GHJK is equivalent to a rectangle with a semicircle removed from both its top side and its bottom side. What is the area of figure GHJK? A. ( – ) ft2 B. ( – ) ft2 C. ( – ) ft2 D. ( – ) ft2

Figure GHJK is equivalent to a rectangle with a semicircle removed from both its top side and its bottom side What is the area of figure GHJK A ft2 B ft2 C ft2 class=

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MathGeek289
Okay, First, Lets Remember The Formulas. Area Of A Rectangle : 
B*H. 
Area Of A Circle:
R*2*3.14. 
16*12 Is The Area Of The Rectangle. 16*12 = 192.
Area Of The Two Semicircles = 6*6*3.14. 6*6 = 36. 36*3.14 =113.04. 
Now, 192-113.04 = 78.96 in ^2. Hope This Helps!
TheHealingHealer
What MathGeek said was pretty correct except for the area of the circle.
The area of a circle is pi r squared, aka pi*radius to the second power.

So, it should be 192 - 36pi ( the radius would be 6, because radius is half the diameter, and 6 to the second power is 36 ).

:D You're welcome.

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