Respuesta :
In a survey of factories in five northeastern states found that 10% of the 300 workers surveyed were satisfied with the benefits offered by their employer, the margin of error for the population proportion is ± seventeen (17) or ± 5.67%.
Answer:
Step-by-step explanation:
Given that A survey of factories in five northeastern states found that 10% of the 300 workers surveyed were satisfied with the benefits offered by their employers
i.e. sample size n =300
Sample proportion p = 0.10
q=1-p=0.9
Std error =[tex]\sqrt{\frac{pq}{n} } =\sqrt{\frac{x0.1(0.9)}{300} } \\=0.01732[/tex]
Margin of error at 95% would be
1.96*std error
= 0.0339=3.39%