Respuesta :

B.

The equation of a circle is:
(x-h)^2 + (y-k)^2 = r^2  -  where (h,k) is the centre and r is the radius

Therefore, a circle with centre (-4,7) and radius 6 has the equation:
(x-(-4))^2 + (y-7)^2 = (6)^2
(x+4)^2 + (y-7)^2 = 36


JeanaShupp

Answer:  B. [tex](x+4)^2+(y-7)^2=36[/tex]

Step-by-step explanation:

We know that the equation  of a circle having center at (h,k) and radius r is given by :-

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Given : The center of the circle : (-4,7)

The radius of the circle : 6 units

Then the equation of a circle with center (-4, 7) and radius 6 will be :-

[tex](x-(-4))^2+(y-7)^2=6^2\\\\\Rightarrow\ (x+4)^2+(y-7)^2=36[/tex]

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