Answer: 0.7748
Step-by-step explanation:
Given : Number of bit bulls at the pound = 18
Number of pit bulls have attacked another dog in the last year =4
The proportion of pit bulls have attacked another dog in the last year:[tex]p=\dfrac{4}{18}\approx0.22[/tex]
Number of the pit bulls selected = 6
The probability of that none of the pit bulls in Joe's group attacked another dog last year : [tex]P(0)=(1-0.22)^6=0.225199600704\approx0.2252[/tex]
By using binomial , the probability that at least one of the pit bulls in Joe's group attacked another dog last year is given by :-
[tex]P(x\geq 1)=1-P(x<1)\\\\=1-P(0)\\\\=1-0.2252=0.7748[/tex]
Hence, the required probability = 0.7748
