Answer:
[tex]\tau=[/tex]2452.5 N/m^2
Explanation:
given:
density [tex]\rho[/tex]=500kg/m^3
viscosity [tex]\mu[/tex]= 10 Pa-s
diameter of tube= 2 m
and L be length
since gravity is the only force shear force will balance it
so we can write
mg= [tex]\tau\times A[/tex]
A= [tex]\rho\times\frac{\pi}{4} d^2\times L[/tex]
m= [tex]\rho\times\frac{\pi}{4} d^2\times L[/tex]
therefore
[tex]\rho\times\frac{\pi}{4} d^2\times Lg= \tau\times{\pi} d\times L[/tex]
putting values we get
[tex]\ 500\times\frac{\pi}{4} 2^2\times g= \tau\times{\pi}\times 2[/tex]
calculating we get [tex]\tau=[/tex]2452.5 N/m^2
