Answer:
The index of refraction of the liquid is 1.35.
Explanation:
It is given that,
Critical angle for a certain air-liquid surface, [tex]\theta_1=47.7^{\circ}[/tex]
Let n₁ is the refractive index of liquid and n₂ is the refractive index of air, n₂ =1
Using Snell's law for air liquid interface as :
[tex]n_1\ sin\theta_1=n_2\ sin(90)[/tex]
[tex]n_1\ sin(47.7)=1[/tex]
[tex]n_1=\dfrac{1}{sin(47.7)}[/tex]
[tex]n_1=1.35[/tex]
So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.
