Answer:
The work done by Joe, W_joe, when he raises the barbell to finish one repetition is 211.98J
The correct option is Wsam <W_Joe.
Explanation:
From the mass of the bar, the acceleration of gravity and the distance that the bar travels in each of them when performing the lifting movement from the chest you can calculate the work done by each one:
W_joe= 31.5kg × 9.81 (m/s^{2} ) × 0.686m = 211.98J
W_sam= 31.5kg × 9.81 (m/s^{2} ) × 0.608m = 187.88J
187.88J < 211.98J ⇒ Wsam <W_Joe