Explanation:
Since, the given reaction is [tex]U + n \rightarrow Xe + Sr + 2n[/tex]
Sum of masses on both reactant and product side is as follows.
235.043924 + 1.008665 = 139.921620 + 93.915367 + (2 × 1.008665)
= 0.198272 u
As it is known that relation between energy and mass is as follows.
Energy produced = [tex]\Delta m c^{2}[/tex]
Since, 1 u = 931.494 MeV/[tex]c^{2}[/tex]. Putting this value into the above formula as follows.
Energy produced = [tex]\Delta m c^{2}[/tex]
= [tex]0.198272 \times \frac{931.494}{c^{2}} \times c^{2}[/tex]
= 184.69 MeV
As 1 MeV equals [tex]1.602 \times 10^{-13}[/tex] joules.
Hence, 184.69 MeV will be converted into joules as follows.
[tex]184.69 MeV \times \frac{1.602 \times 10^{-13}J}{1 MeV}[/tex]
= [tex]295.87 \times 10^{-13}[/tex] J
= [tex]2.95 \times 10^{-17}[/tex] J
Thus, we can conclude that energy released in this reaction is [tex]2.95 \times 10^{-15}[/tex] J.