Answer:
velocity at the out let is equal to 3.18 m/s
Explanation:
height of the second floor = 10 m
pipe diameter(d₁) = 3 cm = 0.03 m
pressure (P₁) = 3 x 10⁵ Pa
diameter at the upstairs (d₂) = 1.5 cm = 0.015 m
A₁ = [tex]\dfrac{\pi}{4}d^2[/tex]
A₁ = [tex]\dfrac{\pi}{4}0.03^2[/tex]
A₁ = 7 × 10⁻⁴ m²
A₂ = [tex]\dfrac{\pi}{4}d^2[/tex]
A₂ = [tex]\dfrac{\pi}{4}0.015^2[/tex]
A₂ = 1.76× 10⁻⁴ m²
using continuity equation
A₁ v₁ = A₂ v₂
7 × 10⁻⁴ × 0.8 = 1.76× 10⁻⁴ × v₂
v₂ = 3.18 m/s
hence velocity at the out let is equal to 3.18 m/s
