Answer:
Probability that at least one head appears is[tex]\frac{6}{7}[/tex]
Step-by-step explanation:
Given : Three fair quarters are tossed, and a tail appears on at least one of them.
To find : What is the probability that at least one head appears?
Solution :
When three fair quarters are tossed the sample form is
[tex]\{HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\}[/tex]
According to question,
In a sample space a tail appears on at least one of them.
i.e. Total outcomes is [tex]\{HHT,HTH,HTT,THH,THT,TTH,TTT\}=7[/tex]
Favorable outcome is getting at least one head appears
i.e. Favorable outcome is [tex]\{HHT,HTH,HTT,THH,THT,TTH\}=6[/tex]
Probability that at least one head appears is
[tex]\text{Probability}=\frac{\text{Favorable outcome }}{\text{Total outcome}}[/tex]
[tex]\text{Probability}=\frac{6}{7}[/tex]
Therefore, Probability that at least one head appears is[tex]\frac{6}{7}[/tex]
