Answer:
1/151200
Step-by-step explanation:
The number of ways to pick an exact order of any 6 different numbers from 10
[tex]_{6}P^{10}\textrm{}[/tex]
=[tex]\frac{10!}{4!}[/tex]
= 10×9×8×7×6×5 = 151200 ways
which means the first one can be any of 10 numbers
The second one can be any of 9 numbers
The 3rd one can be any of 8 numbers and so on
Now the 6th one can be any of 5 numbers
Thus there are 10×9×8×7×6×5 = 151200 ways to choose the number
so the required probability is 1/151200
