Answer:
Work done = 13605.44
Explanation:
Data provided in the question:
For elongation of 2.1 cm (0.021 m) work done by the spring is 3.0 J
The relation between Energy (U) and the elongation (s) is given as:
U = [tex]\frac{1}{2}kx^2[/tex] ................(1)
where,
k is the spring constant
on substituting the valeus in the above equation, we get
3.0 = [tex]\frac{1}{2}k\times0.021^2[/tex]
or
k = 13605.44 N/m
now
for the elongation x = 2.1 + 4.1 = 6.2 cm = 0.062 m
using the equation 1, we have
U = [tex]\frac{1}{2}\times13605.44\times (0.062)^2[/tex]
or
U = 26.149 J
Also,
Work done = change in energy
or
W = 26.149 - 3.0 = 23.149 J
