Answer:[tex]\theta =20.683^{\circ} angle\ of\ refraction[/tex]
Explanation:
Given
Refractive index of glass[tex]\left ( n_2\right )=1.5[/tex]
Angle of incidence [tex]=32^{\circ}[/tex]
Using snell's law
[tex]n_1sin\left ( 32\right )=n_2sin\left ( \theta \right )[/tex]
where [tex]\theta =angle of refraction[/tex]
[tex]1\cdot sin\left ( 32\right )=1.5\cdot sin\left ( \theta \right )[/tex]
[tex]sin\theta =\frac{2\times sin32}{3}[/tex]
[tex]\theta =20.683^{\circ}[/tex]
Similarly ray incident on other side of glas with angle of incidence equals to [tex]\theta [/tex]
and angle of emergence [tex]=31.98 \approx 32[/tex]
