Respuesta :

(For full answer you might have to go to the comments)

Answer: 28x+30

Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
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(x^2+3x+3) 3x^3-2x^2+4x-3


-(3x^3+9x^2+9x)
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-11x^2-5x-3

-(-11x^2-33x-33)
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28x+30

So our remainder will be 28x+30