Respuesta :
Answer:
0.44 m
Explanation:
w₀ = initial angular speed of rotating stool = 10.0 rpm
r₀ = initial distance of weights from axis of rotation = 0.785 m
w = final angular speed = 32.5 rpm
r = final distance of the weights from axis of rotation = ?
m = mass of weights
Using conservation of angular momentum
m r₀² w₀ = m r² w
(0.785)² (10) = r² (32.5)
r = 0.44 m
Answer:
0.44 m
Explanation:
f = 10 rpm = 10 / 60 rps
ω = 2 x 3.14 x 10 / 60 = 1.047 rad/s
f' = 32.5 rpm = 32.5 / 60 rps
ω' = 2 x 3.14 x 32.5 / 60 = 3.4 rad/s
r = 0.785 m
Let the mass of each block be m and the new distance is r'.
As no external torque is there, so angular momentum remains constant
I x ω = I' x ω'
2 m r^2 x ω = 2 m r'^2 x ω'^2
0.785 x 0.785 x 1.047 = r'^2 x 3.4
r'^2 = 0.1898
r' = 0.44 m