Answer:
Step-by-step explanation:
Given that according to the most recent data, 12.3% of engineers (electrical, mechanical, civil, and industrial) were women.
n =80
p is normal with p = 12.3% and std error = [tex]\sqrt{\frac{0.123(0.877}{80} } =0.03672[/tex]
Prob 12 or more women = P(p>0.15)
=P(Z>[tex]\frac{0.15-0.123}{0.03672} =0.74)[/tex]
=0.5-0.2704=0.2296